The hammer hits the nail with a force F [ = – 2500]N. 8. A motor vehicle has a mass of 1500 kg. What must be the force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7 ms-2? NCERT Solutions for Class 9 Science Chapter 9 Force and Laws of Motion updated for 2022-23. Download 9th Science Chapter 9 Intext questions given on page 118, page 126, exercises or additional exercises in English. STUDENTS of MP Board and UP Board can download UP Board Solutions in Hindi Medium here. Hindi Medium Solutions of Class 9 Science Chapter 9 Bal tatha Gati ke Niyam ke Page 131 ke Uttar, Page 140 ke Uttar, Abhyaas ke Uttar ya Atirikt Abhyaas ke Uttar are also available for PDF download or study online for free. NCERT Solutions 2022-23 for Class 9, all materials and offline applications based on these Class 9(ix) solutions are provided free of charge in Hindi and English. Therefore, the force required to reduce the speed is [ = – 6000] N. The truck undergoes a greater impact force (action), this greater impact force is also question 8. Specify Newton`s second law of motion. Answer: The rate of change in the momentum of an object is proportional to the unbalanced force applied in the direction of the force. From the table, we can see that the distance changes unevenly at the same intervals.

Thus, it is said that the object is in uneven motion. As the speed of the object increases over time, the acceleration also increases. 5. A truck starts from rest and hurtles down a hill with constant acceleration. It covers a distance of 400 m in 20 s. Find its acceleration. Find the force acting on them when their mass is 7 tons (note: 1 ton = 1000 kg). Question 4. What is a balanced force? Answer: If the forces acting on a body in the opposite direction do not alter the resting or moving state of an object, these forces are called balanced forces. A: Hit a mat with a stick; As a result, the carpet moves quickly, while dust particles trapped in the pores of the carpet prefer to remain motionless, since the inertia of an object resists any change in its state of rest or movement. According to Newton`s first rule of motion, the dust particles remain at rest as the mat moves. As a result, dust particles escape from the carpet.

Therefore, each person applies a force of [240] N to push the car. The negative sign shows that the force is acting in the opposite direction of the vehicle. Therefore, the acceleration of the truck is [2] m/s2 and the force acting on the truck is F [ = 14000] N We cannot see the force, but by its action we can identify the force. There are various effects of force as explained below – Depending on the mass of the luggage and the force of the force, luggage may fall off the bus due to inertia. Tying the luggage secures its position and prevents it from falling off the bus. Therefore, train acceleration = (net acceleration force) / (total train mass) is question 15. The diagram shows a moving truck. Forces A, B, C and D act on the truck. Name the type of forces acting on a truck. Answer: The forces A, B, C and D acting on the truck are as follows: A force can stop a moving body. For example, brakes that are applied to a moving cycle.

The negative sign indicates that the recoil speed is opposite to the movement of the ball. Question 2. Saksham saw his karate expert break a slate. He tried to break the slate, but Saksham`s friend stopped him and told him it would hurt, you need a lot of practice. (a) How can a karate expert break the slate without injuring his hand? b) What is Newton`s third law of motion? (c) What is the value of Saksham`s friend in the above case? Answer: (a) A karate player performs the move with great speed in a very short time interval on the slate, so that a great force is exerted on the slate and it breaks. b) With each action, there is an equal and opposite reaction, both act on different bodies. Saksham`s friend showed the importance of being a responsible and caring friend. Question 1. Here is the distance-time table on a moving object: (a) What conclusion can you draw about acceleration? Is it constant, up, down or zero? (b) What do you conclude from the forces acting on the object? Answer: According to the given table, the initial velocity of the object is zero.